To solve this problem, we can use the properties of circles, particularly the relationship between a radius and a tangent line at the point of tangency.
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Identify the Circle and the Tangents:
- Let \( O \) be the center of the circle.
- \( K \) is a point outside the circle, and \( KM \) and \( KL \) are tangent lines to the circle at points \( M \) and \( L \), respectively.
- By the properties of tangents, the radius \( OL \) is perpendicular to the tangent line \( KL \) at point \( L \).
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Use of the Right Triangle:
- \( \triangle LFK \) is formed by the radius \( OL \) and the tangent \( KL \).
- Given that \( \angle LFK = 23^\circ \) and the tangent length \( KM = 47 \) feet, we can determine the length of \( LF \).
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Use of Trigonometry:
- In the right triangle \( \triangle LFK \):
- \( LF \) is the opposite side to the angle \( \angle LFK \).
- \( KL \) is the adjacent side, which we need to find.
- In the right triangle \( \triangle LFK \):
Using the tangent function since we know the angle and one side:
\[ \tan(\angle LFK) = \frac{\text{opposite}}{\text{adjacent}} = \frac{LF}{KL} \]
We already know the relationship between the tangents:
\[ KL = KM = 47 \text{ feet} \]
Thus,
\[ \tan(23^\circ) = \frac{LF}{47} \]
Now, calculate \( LF \):
\[ LF = 47 \cdot \tan(23^\circ) \]
- Calculating \( LF \):
Using a calculator to find \( \tan(23^\circ) \):
\[ \tan(23^\circ) \approx 0.4245 \]
Now calculating \( LF \):
\[ LF \approx 47 \cdot 0.4245 \approx 19.93 \]
Rounding to the nearest foot, we find:
\[ LF \approx 20 \text{ feet} \]
Thus, the length of \( LF \) is approximately 20 feet.