I was given this info
r=1.5 m
d=3 m
F= 50 N
angle= 110 degrees
3. The attempt at a solution
T=Fsin
T= (1.5)(50)sin(110)
T=70 J
How do i get (maximum) torque?
r=1.5 m
d=3 m
F= 50 N
angle= 110 degrees
3. The attempt at a solution
T=Fsin
T= (1.5)(50)sin(110)
T=70 J
How do i get (maximum) torque?