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Teejay
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I was given this info
r=1.5 m d=3 m F= 50 N angle= 110 degrees 3. The attempt at a solution T=Fsin T= (1.5)(50)sin(110) T=70 J
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Expand to the general case to explore how the cross product behaves under scalar multiplication k (a x b) = (ka) x b = a x (kb).
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It’s 30
Nic, your solution is a bit confusing as it contains 6+4+7. instead, try this: worms-w-9 bugs-b-10 butterflies-f-3 11b+1w or... 11b+3f 11b=110 1w=9 3f=9 110+9=119 SOLVED!
