Fencing needed= 3Width + 4 length, correct? I don't have your diagram
Area= 2*W*L
so 200=3w+4L so l= (200-3w)/4 putting that into area..
area= 2w(200-4w)/4
I usually know how to do these types of problems, but the second variable just threw me off balance..
47. A rancher has 200 feet of fencing to enclose two adjacent rectangular corrals. What dimensions will produce a maximum enclosed area? (the diagram is of two adjacent corrals sharing a middle fence, y, and each individual corral has length x [so the two together would be 2x for the entire length])
I hope I've explained the diagram enough...any help is greatly appreciated!! :D
2 answers
Ohhhhhh i totally get it now! Thanks!! :D
39 answers