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Convert 9.16 g Ba(OH)2 to moles.
There are two OH^- per mole Ba(OH)2; therefore, moles Ba(OH)2 x 2 = moles OH^-
Then moles OH^-/kg water = m of OH^-
I still need help with this problem...
Calculate the concentration of the solution
the molality of hydroxide ions in a solution prepared from 9.16 g of barium hydroxide dissolved in 179 g of water
I do not know how to approach this...I keep doing something wrong.
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