I am stuck in this problem I need to calculate the molality first so I could find T but I don't know which one is the solvent and which one is the solution the problem is to calculate the freezing point of a solution containing 12.2g of benzoic acid, dissolved in 250g of nitrobenzene the freezing point of nitrobenzene is 5.7 C and its freezing point depression constant is 7.0 C/m. please help

2 answers

Benzoic acid is a solid. Nitrobenzene is a liquid; therefore, mols benzoic acid is 12.2 g/molar mass benzoic acid. The solvent is nitrobenzene and you have 0.250 kg.
thanks
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