First factor x^2-8x+15
You should get
(x-5)(x-3)
Now set each factor equal to zero and solve for x
x-5=0
x-3=0
I really need help with this question. Thanks! Find the zeros of the function algebraically. Be sure to show all work.
f(x)=x^2-8x+15
---------------
10x
3 answers
@Mia, did I do this write?
x^2-8x+15
(x + 3) (x + 5)
x-5=0 x-3=0
The zeros would be x = 3 x = 5
x^2-8x+15
(x + 3) (x + 5)
x-5=0 x-3=0
The zeros would be x = 3 x = 5
Yes