(6x^2-5x)(6x^2+5x)=0
x(6x-5)=0 x(6x+5)=0
x=0 (6x-5)=0 x=0 6x+5=0
6x=5 x=-5/6
x=5/6
Find the zeros of the function algebraically.
f(x) = 36x^4 − 25x^2
x = (smallest value)
x =
x = (largest value)
1 answer