I really need help so please help.

write the first trigonometric function in terms of the second trigonometric function.

sec x; tan x

5 answers

think of sec x as 1/cos x.
oops i take that back
big hint: sec x is the hypotenuse of a triangle with legs tan x and 1.
from
sin^2 Ø + cos^2 Ø = 1
divide each term by cos^2 Ø

sin^2 Ø/cos^2 Ø + 1 = 1/cos^2 Ø

tan^2 Ø + 1 = sec^2 Ø

sec Ø = √(tan^2 Ø + 1)
Thank you, Reiny! It helped me a lot.