I really need help so please help.
write the first trigonometric function in terms of the second trigonometric function.
sec x; tan x
5 answers
think of sec x as 1/cos x.
oops i take that back
big hint: sec x is the hypotenuse of a triangle with legs tan x and 1.
from
sin^2 Ø + cos^2 Ø = 1
divide each term by cos^2 Ø
sin^2 Ø/cos^2 Ø + 1 = 1/cos^2 Ø
tan^2 Ø + 1 = sec^2 Ø
sec Ø = √(tan^2 Ø + 1)
sin^2 Ø + cos^2 Ø = 1
divide each term by cos^2 Ø
sin^2 Ø/cos^2 Ø + 1 = 1/cos^2 Ø
tan^2 Ø + 1 = sec^2 Ø
sec Ø = √(tan^2 Ø + 1)
Thank you, Reiny! It helped me a lot.
2 answers