sec Q = 5 tanQ
1/cosQ = 5sinQ/cosQ
so sinQ = 1/5
I then made a right angles triangle with hypotenuse 5, opposite 1 and let x be the adjacent.
By Pythagoras
x^2 + 1^2 = 5^2
x^2 = 24
x = √24 = 2√6
WOAH!
but you said secQ = 2√6
if, as you started, secQ = 5tanQ, then my calculations stands as correct and
secQ would be 5/(2√6) and not 2√6
I will wait till you correct your opening statement of
sec Q = 5 tan = 2sqrt6 , which leads to a contradiction.
Use the given function values and trigonometric identities (including the relationship between a trigonometric function and its cofunction of a complementary angle) to find the indicated trigonometric functions.
sec Q = 5 tan = 2sqrt6
a) cos Q b) cotQ
c) cot(90 degrees - Q) d) sin Q
Please explain. I do not understand how to do this. Thank you!!
2 answers
What this person means is :
cosQ = 5 and tanQ = 2sqrt6
cosQ = 5 and tanQ = 2sqrt6