It won't help you learn how to do these for me to do them for you. Here are several sites within this one site that tells you how to balance equations as well as the types of reactions. It is important that you understand how to do it. Read through this material and do the best you can, THEN post one question at a time for us to check it. Please include with your post exactly what trouble you have knowing where to go for the next step.
In a supplementary post I will do the first one for you.
I really need help for my homework on how to write the balanced equation for the following reactions.
1) Sodium reacts with iron(lll)oxide to produce sodium oxide and iron.
Type of reaction:
Balanced Equation:
2) Hydrogen bromide forms from hydrogen and bromine.
Type of Reaction:
Balanced Equation:
3) Metallic silver and chlorine gas from silver chloride.
Type of Reaction:
Balanced Equation:
4) Carbon dioxide and water are produced when ethane, C2H6, reacts with oxygen.
Type of Reaction:
Balanced Equation:
5) Calcium oxide reacts with water to form calcium hydroxide.
Type of Reaction:
Balanced Equation:
6) Calcium hydroxide and hydrochloric acid (hydrogen chloride) produce calcium and water.
Type of Reaction:
Balanced Equation:
7) Iron(lll) nitrate reacts with lithium hydroxide to produce lithium nitrate and iron(lll)hydroxide.
Type of Reaction:
Balanced Equation:
8) Iron and oxygen produce iron(lll)oxide.
Type of Reaction:
Balanced Equation:
Carbon dioxide and water are produced when sucrose, C12 H22 O11, reacts with oxygen.
Type of Reaction:
Balanced Equation:
Please help me with these questions because I'm really confuse with this homework and if I do it alone I know I'm going to do most of the work wrong.
Also if there is a writing a balanced equation calculator. I think it should be able to help me find out what the writen blanced equation are when balanced.
4 answers
I didn't post the site.(Broken Link Removed)
1) Sodium reacts with iron(lll)oxide to produce sodium oxide and iron.
Balanced Equation:
Can you write the formulas for each element and compound? The problem TELLS you what the products are.
Na + Fe2O3 ==> Na2O + Fe
To balance, it is a process of trial and error. Rule #1--You MAY NOT (I repeat--may NOT) change any of the subscripts to make the equation balance. Rule #2. You MAY change ONLY the coefficients.
Now, I look at the equation and I see 2 Na atoms on the right from Na2O so we should place a 2 in front of the Na atom on the left.
2Na + Fe2O3 ==> Na2O + Fe
Next, we can balance the Fe by placing a 2 on the right to make 2 Fe atoms.
2Na + Fe2O3 ==> Na2O + 2Fe.
That leaves only oxygen to do and one look tells us we have a problem. We have 3 O atoms on the left and we need to make 3 on the right. To do that we place a 3 for Na2O BUT that messes up the Na you say. You're right. That's the trial and error part. So lets place a 3 for Na2O.
2Na + Fe2O3 ==> 3Na2O + 2Fe
Recount the Na and we see we have 6 on the right so we need to change that 2 for Na on the left to a 6
6Na + Fe2O3 ==> 3Na2O + 2Fe
Now we check everything to see that it is balanced. You can ALWAYS do this (and should) so you will ALWAYS know if the equation is balanced or not.
I see 6 Na on the left and 6 on the right. There are 2 Fe on the left and 2 on the right. There are 3 O on the left and 3 on the right. So everything balances.
Type of reaction: You have a single atom replaces an atom in a compound so this is a single replacement reaction. The Na atom simply replaces the Fe in the compound of Fe2O3 to Fe by itself.
Balanced Equation:
Can you write the formulas for each element and compound? The problem TELLS you what the products are.
Na + Fe2O3 ==> Na2O + Fe
To balance, it is a process of trial and error. Rule #1--You MAY NOT (I repeat--may NOT) change any of the subscripts to make the equation balance. Rule #2. You MAY change ONLY the coefficients.
Now, I look at the equation and I see 2 Na atoms on the right from Na2O so we should place a 2 in front of the Na atom on the left.
2Na + Fe2O3 ==> Na2O + Fe
Next, we can balance the Fe by placing a 2 on the right to make 2 Fe atoms.
2Na + Fe2O3 ==> Na2O + 2Fe.
That leaves only oxygen to do and one look tells us we have a problem. We have 3 O atoms on the left and we need to make 3 on the right. To do that we place a 3 for Na2O BUT that messes up the Na you say. You're right. That's the trial and error part. So lets place a 3 for Na2O.
2Na + Fe2O3 ==> 3Na2O + 2Fe
Recount the Na and we see we have 6 on the right so we need to change that 2 for Na on the left to a 6
6Na + Fe2O3 ==> 3Na2O + 2Fe
Now we check everything to see that it is balanced. You can ALWAYS do this (and should) so you will ALWAYS know if the equation is balanced or not.
I see 6 Na on the left and 6 on the right. There are 2 Fe on the left and 2 on the right. There are 3 O on the left and 3 on the right. So everything balances.
Type of reaction: You have a single atom replaces an atom in a compound so this is a single replacement reaction. The Na atom simply replaces the Fe in the compound of Fe2O3 to Fe by itself.
How many moles of chlorine gas react with 1 mol of hydrogen gas according to the balanced chemical equation?
H2(g) + Cl2(g) → 2 HCl(g)
H2(g) + Cl2(g) → 2 HCl(g)