Asked by Alex
Write the half reactions and the balanced
equation for the galvanic cell
Cu(s)| Cu2+(aq)|| Cu+(aq)| Cu(s).
What is the smallest possible integer coefficient of Cu2+(aq) in the combined balanced equation?
When put together the balanced equation is just Cu + Cu+ = Cu2+ + Cu. So that means that the smallest possible integer coefficient for Cu2+ is just 1, right? If I'm wrong, can you please explain to me why I am wrong?
equation for the galvanic cell
Cu(s)| Cu2+(aq)|| Cu+(aq)| Cu(s).
What is the smallest possible integer coefficient of Cu2+(aq) in the combined balanced equation?
When put together the balanced equation is just Cu + Cu+ = Cu2+ + Cu. So that means that the smallest possible integer coefficient for Cu2+ is just 1, right? If I'm wrong, can you please explain to me why I am wrong?
Answers
Answered by
DrBob222
Is your equation balanced? You know it isn't because the charges don't balance.
Answered by
Alex
So would it be Cu + 2Cu+ = Cu2+ + 2Cu? I didn't change the electrons before for the half reaction.
Answered by
DrBob222
or cancel 1 Cu(s) for
2Cu^+ ==> Cu^2+ + Cu which is the disproportionation reaction for Cu^+. 1 goes down to Cu(s) and the other goes up to Cu^2+.
2Cu^+ ==> Cu^2+ + Cu which is the disproportionation reaction for Cu^+. 1 goes down to Cu(s) and the other goes up to Cu^2+.
Answered by
betsychemAPstudent
It should be 1, because the final balanced equation is 2Cu+ + Cu --> Cu2+ + 2Cu
Therefore, your answer is 1, because as you can see, the Cu^2+ has a coefficient of 1
this is because you combine the following half-reactions:
(1) Cu--> Cu 2+ + 2e-
(2) 2Cu + 2e- --> 2Cu
btw the second half-reaction has coefficients of 2 because I multiplied the entire equation by 2 in order to cancel out the 2 electrons on the product side of the first half reaction.
Therefore, your answer is 1, because as you can see, the Cu^2+ has a coefficient of 1
this is because you combine the following half-reactions:
(1) Cu--> Cu 2+ + 2e-
(2) 2Cu + 2e- --> 2Cu
btw the second half-reaction has coefficients of 2 because I multiplied the entire equation by 2 in order to cancel out the 2 electrons on the product side of the first half reaction.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.