solve for sinC. SinC=13.5(sin126.5deg)/17.2=.65
C= arcsin .65= 40.5 deg
B=180-A-C
then finally, use law of sines to find side b.
I need to solve the rest of the triangle
A=126.5
a=17.2
c=13.5
Using the Law of Sines we get
a/sinA = c/sin C
17.2/sin126.5 = 13.5/sinc
I am confused on what to do next
3 answers
I understand the rest of the question. I am just having some problems understanding the first.
How did
17.2/sin126.5deg = 13.5/sin C
turn into
SinC=13.5(sin126.5deg)/17.2=.65
How did
17.2/sin126.5deg = 13.5/sin C
turn into
SinC=13.5(sin126.5deg)/17.2=.65
I get it now. You need to Cross-Multiply