You will find lots of information here,
the first page is not bad
http://www.google.ca/#hl=en&source=hp&q=solving+triangles%2C+the+ambiguous+case&btnG=Google+Search&meta=&aq=f&oq=solving+triangles%2C+the+ambiguous+case&fp=b664983305b547ce
Determine whether the given information resutls in one triangle, two triangles, or no triangle at all. Solve any triangle(s) that results.
b = 4
c = 6
beta = 20
Ok...
I checked my answers in the back of the book and got the first triangle right
Gamma = 30.9
alpha = 129.1
a = 9.1
this is the law of sine stuff
ok also my teacher says that if a second triangle exists...
beta two would be equal to 180 - beta one because it would be an isocoles triangle so
180 - 20 gives me 160
alpha is the same which is 129.1 which is correct according to the back of the book
which runs into a problem because 160 + 129.1 gives me more than 180 degrees
for the second triangle the back of the book says
Gamma 2 = 149.1
alpha 2 = 10.9
a2 = 2.20
aparently then
beta 2 is equal to what?
it's not given in the back
b is not in the book but it would be the same as the first triangle... 4
and I thought a would be 9,1 because it would be the same as the first triangle but apparently i'm wrong
also for some reason c is not given in the back of the book...
So I don't get this what am I not getting here???
My teacher told me in lecture that in problems like this that side a would be the same in both triangles and there would be an issoceles angle and so with two angle betas that would be equal to each other and beta two could be found by taking 180 - beta one sense they are suplementary so I don't get it...
1 answer
1 answer