This is an integral in the form of
INT f'(x)/f(x) dx
it integrates to ln |(f(x))|
http://en.wikipedia.org/wiki/Table_of_integrals
I need to find the integral:
int:(x^2+2x+3)/(x^3+3x+9) dx
I think I am supposed to use the rule: int:1/u du=ln|u|+C
But I don't know what to do first.
Thanks for your help! :-)
Oh- and the answer the back of my book gives is (1/3)ln|x^3+3x^2+9x|+C
2 answers
Thanks for your help! :-)
I think I got the answer!
Thanks1
I think I got the answer!
Thanks1