I need the answers

Question

Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 453 N and F2 = 400 N. (Assume up and to the right as positive directions.)(F1 is 8degrees and F2 is 35degreed)
(a) What is the resultant of these two forces?
magnitude
direction

(b) If the car has a mass of 3805 kg, what acceleration does it have? Ignore friction.

Answer 1

a. Fr = 453N.[8o] + 400N.[35o].
Fr = x+yi = (453*Cos8+ 400*Cos35) + (453*sin8+400*sin35)I.
Fr = 776.3 + 292.5i = 829.6N.[20.6o].

b. Fr = M*a.
a = Fr/M = 829.6[20.6]/3805 = 0.218m/s^2[20.6o].