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Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 439 N and F2 = 365 N. (As...Asked by Anonymous
Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 443 N and F2 = 372 N. (Assume up and to the right as positive directions.)
(a) What is the resultant of these two forces?
magnitude N
direction ° to the right of the forward direction
(b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction.
m/s2
(a) What is the resultant of these two forces?
magnitude N
direction ° to the right of the forward direction
(b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction.
m/s2
Answers
Answered by
Steve
if you understand interpolation, and you seem to, just think of it this way.
If the value you want is, say, 2/3 of the way from one known value to the next, the readings will also be 2/3 of the way from one value to the next.
so, if you want to place values at 1-unit intervals, you need to step through the given timestamps and whenever you find two timestamps greater than one unit apart, interpolate.
3 and 4.5 are greater than 1 unit apart, so, since 4 is 2/3 of the way between 3 and 4.5, you will generate values 2/3 of the way between those at 3, and those at 4.5.
Since 7 is more than 1 unit away from 4.5, you need to generate data points for times of 5 and 6.
5 is 1/5 of the way from 4 to 7.5
6 is 3/5 of the way.
so, given x-values and y-values,
if x<sub>n+1</sub> - x<sub>n</sub> > 1,
for each number x<sub>k</sub> between x<sub>n</sub> and x<sub>n+1</sub>,
y<sub>k</sub> = y<sub>n</sub> + (x<sub>k</sub>-x<sub>n</sub>)/(x<sub>n+1</sub>-x<sub>n</sub>) * (y<sub>n+1</sub>-y<sub>n</sub>)
If the value you want is, say, 2/3 of the way from one known value to the next, the readings will also be 2/3 of the way from one value to the next.
so, if you want to place values at 1-unit intervals, you need to step through the given timestamps and whenever you find two timestamps greater than one unit apart, interpolate.
3 and 4.5 are greater than 1 unit apart, so, since 4 is 2/3 of the way between 3 and 4.5, you will generate values 2/3 of the way between those at 3, and those at 4.5.
Since 7 is more than 1 unit away from 4.5, you need to generate data points for times of 5 and 6.
5 is 1/5 of the way from 4 to 7.5
6 is 3/5 of the way.
so, given x-values and y-values,
if x<sub>n+1</sub> - x<sub>n</sub> > 1,
for each number x<sub>k</sub> between x<sub>n</sub> and x<sub>n+1</sub>,
y<sub>k</sub> = y<sub>n</sub> + (x<sub>k</sub>-x<sub>n</sub>)/(x<sub>n+1</sub>-x<sub>n</sub>) * (y<sub>n+1</sub>-y<sub>n</sub>)
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