If you mean the nth term is
-4 (1/3)^(n-1)
then clearly you have a GP where
a = -4
r = 1/3
The terms are
-4, -4/3, -4/9, ...
The sum is thus
a/(1-r) = -4/(2/3) = -6
I need steps on how to complete this please i am so confused and lost. :(
Consider the infinite geometric series x e n=1 -4(1/3) n-1. In this image, the lower limit of the summation notation is "n=1".
a. Write the first four terms of the series.
b. Does the series diverge of converge?
c. If the series has a sum, find the sun.
1 answer
1 answer