if x = -1, 2x+3 = 1 and -f(1) = -4
if x = 0, 2x+3 = 3 and -f(3) = -10
etc
I need help with this question.
Suppose that f(0)= 0 , f(1)= 4, f(2)= 4, f(3)= 10, f(4)= 16 and g(x) = -f(2x+3). Find any 5 points on g(x).
6 answers
you have f for 0,1,2,3,4
Clearly, since
g(x) = -f(2x+3)
g(-3/2) = -f(0) = 0 so (-3/2,0)
g(-1) = -f(1) = -4 so (-1,-4)
and so on
Clearly, since
g(x) = -f(2x+3)
g(-3/2) = -f(0) = 0 so (-3/2,0)
g(-1) = -f(1) = -4 so (-1,-4)
and so on
I still don't understand.
Steve and I both said the same thing in different ways. Here is another.
like when is 2x+3 = 0 ???
when x = -3/2
so what is f(0)
it is 0
so when x = -3/2 then g(x) = 0
like when is 2x+3 = 0 ???
when x = -3/2
so what is f(0)
it is 0
so when x = -3/2 then g(x) = 0
ok tell me if i did this question correct. I just worked out the question.
-f(0) =(-3/2, 0)
-f(1) =(-1, -4)
-f(2) =(-1/2, -4)
-f(3) =(0 , -10)
-f(4) =(1/2, -16)
-f(0) =(-3/2, 0)
-f(1) =(-1, -4)
-f(2) =(-1/2, -4)
-f(3) =(0 , -10)
-f(4) =(1/2, -16)
looks good to me.