Question

I need help with this question.

Suppose that f(0)= 0 , f(1)= 4, f(2)= 4, f(3)= 10, f(4)= 16 and g(x) = -f(2x+3). Find any 5 points on g(x).

Answer 1

if x = -1, 2x+3 = 1 and -f(1) = -4

if x = 0, 2x+3 = 3 and -f(3) = -10
etc

Answer 2

you have f for 0,1,2,3,4
Clearly, since
g(x) = -f(2x+3)
g(-3/2) = -f(0) = 0 so (-3/2,0)
g(-1) = -f(1) = -4 so (-1,-4)
and so on

Answer 3

I still don't understand.

Answer 4

Steve and I both said the same thing in different ways. Here is another.

like when is 2x+3 = 0 ???
when x = -3/2

so what is f(0)
it is 0

so when x = -3/2 then g(x) = 0

Answer 5

ok tell me if i did this question correct. I just worked out the question.

-f(0) =(-3/2, 0)
-f(1) =(-1, -4)
-f(2) =(-1/2, -4)
-f(3) =(0 , -10)
-f(4) =(1/2, -16)

Answer 6

looks good to me.