think back, back, back to your days in trig.
If the tower has height h,
tan 67 = h/50
h = 117.8 m
I need help with the following problem: From a point 50 meters from the bottom of a radio tower along level ground, the angle of elevation to the top of the tower is 67 degrees. What is the height of the tower?
3 answers
to solve this problem we need trigonometry therefore takes the radiant
67°*3,14/180=1,17 rad.= a
point P=50m
height tower H=?
L=hypotenuse of the right triangle LPH
P=Lcos(a)=> (i)L=p/cos(a)
(ii)H=Lsen(a)
(i)+(ii)H=[p/cs(a)]*sn(a)
tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m
67°*3,14/180=1,17 rad.= a
point P=50m
height tower H=?
L=hypotenuse of the right triangle LPH
P=Lcos(a)=> (i)L=p/cos(a)
(ii)H=Lsen(a)
(i)+(ii)H=[p/cs(a)]*sn(a)
tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m
From my view. Tan=opp/adj
Therefore when u cross multiply u have
50tan67
H=82.6m
Approx. 83m
Therefore when u cross multiply u have
50tan67
H=82.6m
Approx. 83m