What mass does that 7.0 mL vinegar have? You need the mass or the density of the vinegar to calculate that.
NaOH + CH3COOH --> CH3COONa + H2O
mols NaOH = M x L = ?
mols CH3OOH = mols NaOH since the equation tells you 1 mol NaOH = 1 mol CH3COOH.
Then grams CH3COOH = mols CH3OOH x molar mass CH3COOH.
% by mass = (g CH3COOH/mass sample)* 100 = ?
mass sample either my weighing or use density. mass = volume x density = 7.0 mL x density which is approx 1.1 g/mL or so.
Or you can calculate % w/v and that is
% w/v = (grams CH3COOH/7.0)*100 = ?
I need help with how to do this!
-If a 7.0mL sample of vinegar was titrated to the stoichiometric equivalence point with 7.5mL of 1.5M NaOH, what is the mass percent of CH3COOH in the vinegar sample?
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