I need help solving this problem.
logbase5(x+2)=2
3 answers
Hint: what is the inverse of the logarithm?
b^logb(z) = z
5^log5 (x+2) = x+2
x+2 = 5^2 = 25
x = 23
5^log5 (x+2) = x+2
x+2 = 5^2 = 25
x = 23
Thank you so much!