I need help on this following problem: The length of a rectangle measures 1 cm less than its width. The perimeter of the rectangle is 106 cm. Find the dimensions of the rectangle. Now i have tried to solve this problem in multiple attempts as can be seen here: 54+53=107, 53+52=105, 48+49=97, 50+49=99. Can you please help me solve this or solve it for me please!! Either choice is appreciated :)

Answer 1

2(w + w-1) = 106
4w-2 = 106
4w = 108
w = 27

so, the width is 27 and the length is 26.

An odd way to assign the dimensions, I must say...

You forgot that the perimeter is twice the sum of the length and width.