L + 1 = W
2L + 2W = 106 (perimeter)
Substitute L+1 for W in the second equation and solve for L. Insert that value into the first equation to solve for W. Check by putting both values into the second equation.
I need help on this following problem: The length of a rectangle measures 1 cm less than its width. The perimeter of the rectangle is 106 cm. Find the dimensions of the rectangle. Now i have tried to solve this problem in multiple attempts as can be seen here: 54+53=107, 53+52=105, 48+49=97, 50+49=99. Can you please help me solve this or solve it for me please!! Either choice is appreciated :)
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