I need help on math 7 a Lesson 4: Adding and Subtracting Rational Numbers
Essential Math 7 A Unit 4: Operations with Fractions Quiz.
61 answers
its at connexcus btw
May someone respawn to me please!
7th grade
Most authors use which point of view in an informational text?(1 point)
a subjective
b connotative
c first-person
d objective
a subjective
b connotative
c first-person
d objective
We don't have the lessons to which you refer us.
Bob (not teacher bob) Use a calculator and your book
need help
I don't know if you're going to see this but pearson is hard and its my last year in middle and you should try kahan Academy it really helps me, understand a lesson on peason.
give the question and answers
1. A or -1/6
2. D or -9 and 7/10
3. D or 7/8
4. A or -1 and 3/10
5. D or 8 and 4/5
There are the answers u people are begging for
also it is lesson 4.4.7 on connexus
2. D or -9 and 7/10
3. D or 7/8
4. A or -1 and 3/10
5. D or 8 and 4/5
There are the answers u people are begging for
also it is lesson 4.4.7 on connexus
1: A
2: C
3: D
4: A
5: B
100% right checked it myself
2: C
3: D
4: A
5: B
100% right checked it myself
nova is wrong i got 60% thanks a lot. :( T-T
Thanks Answers for connexus for the right answers i wish i wouldve used them
Thanks Answers for connexus for the right answers i wish i wouldve used them
here are all the answers
1: D
2: A
3: A
4: C
5: A
100% trust me
1: D
2: A
3: A
4: C
5: A
100% trust me
omg thanks
TYSM
100% hes right 100%
the answers are
1.A
2.D
3.D
4.A
5.D
trust me the other answers are wrong
1.A
2.D
3.D
4.A
5.D
trust me the other answers are wrong
there is 8 for me???
doe anybody have the answers to the math 7A lesson 5 property shmoperties quiz please i really need the help
there is 8 for me to
Adding and Subtracting Rational Numbers Quick Check:
A
D
D
A
D
A
D
D
A
D
1.A
2.C.
3.D
4.A
5.B
01/02/21
2.C.
3.D
4.A
5.B
01/02/21
STOP CHEETING
There are 30 for me LOL
Bloody Hell, thankyou so much Kathryn. I got a 100% percent thanks to you ;)
Mr prezily offical,
Why are you here then O_o hm? OH i KNOW WHY!!!!! because you're here looking for answers as well :l so i dont know what u r complaining about. You're here to. So dont complain and tell us not to cheat. I STUDY HERE with my CLASSMATES not CHEAT LIKE U :V
Why are you here then O_o hm? OH i KNOW WHY!!!!! because you're here looking for answers as well :l so i dont know what u r complaining about. You're here to. So dont complain and tell us not to cheat. I STUDY HERE with my CLASSMATES not CHEAT LIKE U :V
There randomized
Love you
f^2 x f^3
f^5, because when you have the same base and you're multiplying exponents, you add the exponents. In this case, f has an exponent of 2 and an exponent of 3, so 2+3=5.
100^12
100^8
100^8
To simplify 100^12, you multiply 100 by itself 12 times, which is equal to 100,000,000,000,000,000,000,000.
For 100^8, you multiply 100 by itself 8 times, which is equal to 100,000,000.
For 100^8, you multiply 100 by itself 8 times, which is equal to 100,000,000.
100^12
_____
100^8
_____
100^8
To divide these two powers with the same base (100), you can subtract the exponent of the denominator from the exponent of the numerator:
100^12 / 100^8 = 100^(12-8) = 100^4
Therefore, the simplified form of 100^12 / 100^8 is 100^4.
100^12 / 100^8 = 100^(12-8) = 100^4
Therefore, the simplified form of 100^12 / 100^8 is 100^4.
x^16
___
x^3
___
x^3
x^16 divided by x^3
When you divide two like bases with exponents, you can subtract the exponent in the denominator from the exponent in the numerator.
In this case, x is the base and the exponent in the numerator is 16 and the exponent in the denominator is 3. Therefore:
x^16 / x^3 = x^(16-3) = x^13
So, the simplified form of x^16 / x^3 is x^13.
In this case, x is the base and the exponent in the numerator is 16 and the exponent in the denominator is 3. Therefore:
x^16 / x^3 = x^(16-3) = x^13
So, the simplified form of x^16 / x^3 is x^13.
which following expression
4^3 x 4^5 < 4^12
5^2 x 5^3 > 5^5
3^2 x 3^4 = 3^2
5^2 x 5^4 = 5^8
4^3 x 4^5 < 4^12
5^2 x 5^3 > 5^5
3^2 x 3^4 = 3^2
5^2 x 5^4 = 5^8
The correct inequality is `4^3 x 4^5 < 4^12`. This can be simplified to `4^8 < 4^12`, which is true since 4^8 is less than 4^12.
The correct inequality is `5^2 x 5^3 < 5^5`. This can be simplified to `5^5 < 5^5`, which is false since 5^5 is equal to 5^5, not less than it.
The correct equation is `3^2 x 3^4 = 3^6`. This is true because when you multiply two like bases, you add the exponents. In this case, 2+4=6, so `3^2 x 3^4 = 3^6`.
The correct equation is `5^2 x 5^4 = 5^6`. This is true because when you multiply two like bases, you add the exponents. In this case, 2+4=6, so `5^2 x 5^4 = 5^6`.
The correct inequality is `5^2 x 5^3 < 5^5`. This can be simplified to `5^5 < 5^5`, which is false since 5^5 is equal to 5^5, not less than it.
The correct equation is `3^2 x 3^4 = 3^6`. This is true because when you multiply two like bases, you add the exponents. In this case, 2+4=6, so `3^2 x 3^4 = 3^6`.
The correct equation is `5^2 x 5^4 = 5^6`. This is true because when you multiply two like bases, you add the exponents. In this case, 2+4=6, so `5^2 x 5^4 = 5^6`.
which following expressions is true?
4^3 x 4^5 < 4^12
5^2 x 5^3 > 5^5
3^2 x 3^4 = 3^2
5^2 x 5^4 = 5^8
4^3 x 4^5 < 4^12
5^2 x 5^3 > 5^5
3^2 x 3^4 = 3^2
5^2 x 5^4 = 5^8
The true expression is `4^3 x 4^5 < 4^12`.
To simplify this expression:
- `4^3` is equal to 64 since 4 multiplied by itself three times equals 64.
- `4^5` is equal to 1,024 since 4 multiplied by itself five times equals 1,024.
- `4^12` is equal to 167,772,16 since 4 multiplied by itself 12 times equals 167,772,16.
So we can rewrite the inequality as:
64 x 1,024 < 167,772,16
When we multiply 64 and 1,024 we get 65,536, which is indeed less than the value of `4^12`, so the inequality is true.
To simplify this expression:
- `4^3` is equal to 64 since 4 multiplied by itself three times equals 64.
- `4^5` is equal to 1,024 since 4 multiplied by itself five times equals 1,024.
- `4^12` is equal to 167,772,16 since 4 multiplied by itself 12 times equals 167,772,16.
So we can rewrite the inequality as:
64 x 1,024 < 167,772,16
When we multiply 64 and 1,024 we get 65,536, which is indeed less than the value of `4^12`, so the inequality is true.
which of the following expression is true?
2^4 x 2^3 = 2^12
3^3 x 3^6 > 3^8
4^2 x 4^2 > 4^4
5^5 x 5^2 = 5^10
2^4 x 2^3 = 2^12
3^3 x 3^6 > 3^8
4^2 x 4^2 > 4^4
5^5 x 5^2 = 5^10
The true expression is `2^4 x 2^3 = 2^7`.
When you multiply two like bases, you add the exponents. In this case, `2^4` is equal to 16, and `2^3` is equal to 8, so `2^4 x 2^3` is equal to `16 x 8`, which is equal to 128, or `2^7`.
Therefore, the expression `2^4 x 2^3 = 2^7` is true.
When you multiply two like bases, you add the exponents. In this case, `2^4` is equal to 16, and `2^3` is equal to 8, so `2^4 x 2^3` is equal to `16 x 8`, which is equal to 128, or `2^7`.
Therefore, the expression `2^4 x 2^3 = 2^7` is true.
write the value of the equation
4^5 divided by 4^5
4^5 divided by 4^5
The value of `4^5 divided by 4^5` is 1.
When you divide two like bases with exponents, you can subtract the exponent in the denominator from the exponent in the numerator.
In this case, `4` is the base and the exponent in the numerator is 5, and the exponent in the denominator is also 5. So:
`4^5 / 4^5` can be simplified to `4^(5-5)`, which is `4^0`.
Any number (except for 0) raised to the power of 0 is equal to 1. Therefore, the value of `4^5 / 4^5` is 1.
When you divide two like bases with exponents, you can subtract the exponent in the denominator from the exponent in the numerator.
In this case, `4` is the base and the exponent in the numerator is 5, and the exponent in the denominator is also 5. So:
`4^5 / 4^5` can be simplified to `4^(5-5)`, which is `4^0`.
Any number (except for 0) raised to the power of 0 is equal to 1. Therefore, the value of `4^5 / 4^5` is 1.
2^2 divided by 2^5
To divide two like bases with exponents, you can use the rule where you subtract the exponent in the denominator from the exponent in the numerator.
In this case, `2` is the base, and the exponent in the numerator is `2`, and the exponent in the denominator is `5`. So `2^2 / 2^5` can be simplified as follows:
`2^2 / 2^5 = 2^(2-5) = 2^(-3)`
The negative exponent means that the base is in the denominator. So the value of `2^2 / 2^5` is `1/2^3` or `1/8`.
In this case, `2` is the base, and the exponent in the numerator is `2`, and the exponent in the denominator is `5`. So `2^2 / 2^5` can be simplified as follows:
`2^2 / 2^5 = 2^(2-5) = 2^(-3)`
The negative exponent means that the base is in the denominator. So the value of `2^2 / 2^5` is `1/2^3` or `1/8`.
(2.3 x 10^1)(7 x 10^6)
To multiply two numbers in scientific notation, you can multiply their coefficients and add their exponents.
Using this rule, we can multiply `(2.3 x 10^1)(7 x 10^6)` as follows:
`(2.3 x 10^1)(7 x 10^6) = (2.3 x 7) x 10^(1+6)`
`= 16.1 x 10^7`
So `(2.3 x 10^1)(7 x 10^6)` is equal to `16.1 x 10^7` in scientific notation.
Using this rule, we can multiply `(2.3 x 10^1)(7 x 10^6)` as follows:
`(2.3 x 10^1)(7 x 10^6) = (2.3 x 7) x 10^(1+6)`
`= 16.1 x 10^7`
So `(2.3 x 10^1)(7 x 10^6)` is equal to `16.1 x 10^7` in scientific notation.
(1.1 x 10^-5)(3 x 10^-2)
To multiply two numbers in scientific notation, multiply their coefficients and add their exponents.
Using this rule, we can multiply `(1.1 x 10^-5)(3 x 10^-2)` as follows:
`(1.1 x 10^-5)(3 x 10^-2) = (1.1 x 3) x 10(-5-2)`
`= 3.3 x 10^-7`
So `(1.1 x 10^-5)(3 x 10^-2)` is equal to `3.3 x 10^-7` in scientific notation.
Using this rule, we can multiply `(1.1 x 10^-5)(3 x 10^-2)` as follows:
`(1.1 x 10^-5)(3 x 10^-2) = (1.1 x 3) x 10(-5-2)`
`= 3.3 x 10^-7`
So `(1.1 x 10^-5)(3 x 10^-2)` is equal to `3.3 x 10^-7` in scientific notation.
7t^4 x 7t^4
To multiply two monomials with the same base, you keep the base and add the exponents.
In this case, the monomials are `7t^4` and `7t^4`. Since both monomials have the same base (`7t^4`), you can multiply them as follows:
`7t^4 x 7t^4 = (7 x 7) x (t^4 x t^4)`
`= 49 x t^(4+4)`
`= 49t^8`
So `7t^4 x 7t^4` simplifies to `49t^8`.
In this case, the monomials are `7t^4` and `7t^4`. Since both monomials have the same base (`7t^4`), you can multiply them as follows:
`7t^4 x 7t^4 = (7 x 7) x (t^4 x t^4)`
`= 49 x t^(4+4)`
`= 49t^8`
So `7t^4 x 7t^4` simplifies to `49t^8`.
-x(7x-8)
To multiply `-x(7x-8)`, you need to distribute `-x` to each term inside the parentheses.
So:
`-x(7x-8) = -x * 7x + (-x) * (-8)`
`= -7x^2 + 8x`
Therefore, `-x(7x-8)` simplifies to `-7x^2 + 8x`.
So:
`-x(7x-8) = -x * 7x + (-x) * (-8)`
`= -7x^2 + 8x`
Therefore, `-x(7x-8)` simplifies to `-7x^2 + 8x`.
3k^2(-2k^2-4k+7
To multiply `3k^2(-2k^2-4k+7)`, you will need to distribute the `3k^2` to each term inside the parentheses.
So:
`3k^2(-2k^2-4k+7) = 3k^2*(-2k^2) + 3k^2*(-4k) + 3k^2*(7)`
`= -6k^4 - 12k^3 + 21k^2`
Therefore, `3k^2(-2k^2-4k+7)` simplifies to `-6k^4 - 12k^3 + 21k^2`.
So:
`3k^2(-2k^2-4k+7) = 3k^2*(-2k^2) + 3k^2*(-4k) + 3k^2*(7)`
`= -6k^4 - 12k^3 + 21k^2`
Therefore, `3k^2(-2k^2-4k+7)` simplifies to `-6k^4 - 12k^3 + 21k^2`.
(3k + 2)(k - 3)
To multiply `(3k + 2)(k - 3)`, you can use the FOIL method which stands for:
- First: multiply the first terms in each set of parentheses
- Outer: multiply the two terms on the outside (the first term in the first set of parentheses and the second term in the second set of parentheses)
- Inner: multiply the two terms on the inside (the second term in the first set of parentheses and the first term in the second set of parentheses)
- Last: multiply the last terms in each set of parentheses
So:
`(3k + 2)(k - 3) = 3k * k + 3k * (-3) + 2 * k + 2 * (-3)`
`= 3k^2 - 9k + 2k - 6`
`= 3k^2 - 7k - 6`
Therefore, `(3k + 2)(k - 3)` simplifies to `3k^2 - 7k - 6`.
- First: multiply the first terms in each set of parentheses
- Outer: multiply the two terms on the outside (the first term in the first set of parentheses and the second term in the second set of parentheses)
- Inner: multiply the two terms on the inside (the second term in the first set of parentheses and the first term in the second set of parentheses)
- Last: multiply the last terms in each set of parentheses
So:
`(3k + 2)(k - 3) = 3k * k + 3k * (-3) + 2 * k + 2 * (-3)`
`= 3k^2 - 9k + 2k - 6`
`= 3k^2 - 7k - 6`
Therefore, `(3k + 2)(k - 3)` simplifies to `3k^2 - 7k - 6`.
(-y+4)(2y-1)
To multiply `(-y + 4)(2y - 1)`, you can again use the FOIL method:
- First: Multiply the first term of each expression: `-y * 2y = -2y^2`
- Outer: Multiply the outer two terms: `-y * -1 = y`
- Inner: Multiply the inner two terms: `4 * 2y = 8y`
- Last: Multiply the last term of each expression: `4 * -1 = -4`
Putting it all together:
`(-y + 4)(2y - 1) = -2y^2 + y + 8y - 4 = -2y^2 + 9y - 4`
Therefore, `(-y + 4)(2y - 1)` simplifies to `-2y^2 + 9y - 4`.
- First: Multiply the first term of each expression: `-y * 2y = -2y^2`
- Outer: Multiply the outer two terms: `-y * -1 = y`
- Inner: Multiply the inner two terms: `4 * 2y = 8y`
- Last: Multiply the last term of each expression: `4 * -1 = -4`
Putting it all together:
`(-y + 4)(2y - 1) = -2y^2 + y + 8y - 4 = -2y^2 + 9y - 4`
Therefore, `(-y + 4)(2y - 1)` simplifies to `-2y^2 + 9y - 4`.
22 answers