Question

I Need Help ?
I'm Suppose to graph this and the domain and range,
How Do i find this ?

1) f(x)=x^2+4 ; x= -3, -2, -1, 0, 1, 2, 3

2)G(x)= squareroot of x+3 ; x= -3, -2, 1, 6

3.H(x)= |x|-4 ; x= -3,-2,-1,0,1,2,3

4.f(x)=4 ; x= -3,-2,-1,0,1,2,3

5.G(x)=x^3+1 ; x= -2,-1,0,1,2

Answer 1

plot the given points. For example, in #1, evaluate x^2+4 for each given x-value:
f(-3) = (-3)^2+4 = 9+4 = 13
and so on.

the graph sketch should help determine the range.
The domain of any polynomial is all reals.
squareroot(z) has domain z >= 0.

Answer 2

Is This the right range and domain for #1?

1. domain:(-0,0)

range: (4,0)

Answer 3

for problem 2 do i square root everything and then do the problem?

Answer 4

#1. You are almost correct, if you meant (-∞,∞) and [4,∞)

Foe #2, √(x+3) means you plot
(-3,0), (-2,1), (1,2), and (6,3)
domain: you need (x+3) >= 0, or x >= -3. That is, [-3,∞)
range: [0,∞)

Answer 5

Thank you!
and for problem 2 shouldn't it be 9?
I don't know for some reason i got 9.
and
Can you check these answers?
For problems 3,4,5

3.Domain:(-∞,∞)
Range:(0,∞)

4.Domain:(-∞,∞)
Range:y=4

5.Domain:(-∞,∞)
range:(-∞,∞)

Answer 6

#2: shouldn't *what* be 9?

#3: range of |x| is [0,∞), so the range of |x|-4 is [-4,∞)

#4: correct

#5: correct

Answer 7

Thanks Again!
and #2 when i pugged everything in i got 9 instead of 6.

Answer 8

I'm still lost on #2. What do you mean "plug everything in"?

where did I get 6? The only 6 I see is the last given value for x. √(6+3) = √9 = 3.

Show me your calculation. Saying you got 9 doesn't tell me how you got it.