plot the given points. For example, in #1, evaluate x^2+4 for each given x-value:
f(-3) = (-3)^2+4 = 9+4 = 13
and so on.
the graph sketch should help determine the range.
The domain of any polynomial is all reals.
squareroot(z) has domain z >= 0.
I Need Help ?
I'm Suppose to graph this and the domain and range,
How Do i find this ?
1) f(x)=x^2+4 ; x= -3, -2, -1, 0, 1, 2, 3
2)G(x)= squareroot of x+3 ; x= -3, -2, 1, 6
3.H(x)= |x|-4 ; x= -3,-2,-1,0,1,2,3
4.f(x)=4 ; x= -3,-2,-1,0,1,2,3
5.G(x)=x^3+1 ; x= -2,-1,0,1,2
8 answers
Is This the right range and domain for #1?
1. domain:(-0,0)
range: (4,0)
1. domain:(-0,0)
range: (4,0)
for problem 2 do i square root everything and then do the problem?
#1. You are almost correct, if you meant (-∞,∞) and [4,∞)
Foe #2, √(x+3) means you plot
(-3,0), (-2,1), (1,2), and (6,3)
domain: you need (x+3) >= 0, or x >= -3. That is, [-3,∞)
range: [0,∞)
Foe #2, √(x+3) means you plot
(-3,0), (-2,1), (1,2), and (6,3)
domain: you need (x+3) >= 0, or x >= -3. That is, [-3,∞)
range: [0,∞)
Thank you!
and for problem 2 shouldn't it be 9?
I don't know for some reason i got 9.
and
Can you check these answers?
For problems 3,4,5
3.Domain:(-∞,∞)
Range:(0,∞)
4.Domain:(-∞,∞)
Range:y=4
5.Domain:(-∞,∞)
range:(-∞,∞)
and for problem 2 shouldn't it be 9?
I don't know for some reason i got 9.
and
Can you check these answers?
For problems 3,4,5
3.Domain:(-∞,∞)
Range:(0,∞)
4.Domain:(-∞,∞)
Range:y=4
5.Domain:(-∞,∞)
range:(-∞,∞)
#2: shouldn't *what* be 9?
#3: range of |x| is [0,∞), so the range of |x|-4 is [-4,∞)
#4: correct
#5: correct
#3: range of |x| is [0,∞), so the range of |x|-4 is [-4,∞)
#4: correct
#5: correct
Thanks Again!
and #2 when i pugged everything in i got 9 instead of 6.
and #2 when i pugged everything in i got 9 instead of 6.
I'm still lost on #2. What do you mean "plug everything in"?
where did I get 6? The only 6 I see is the last given value for x. √(6+3) = √9 = 3.
Show me your calculation. Saying you got 9 doesn't tell me how you got it.
where did I get 6? The only 6 I see is the last given value for x. √(6+3) = √9 = 3.
Show me your calculation. Saying you got 9 doesn't tell me how you got it.