The answer is
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(x+3)sqrt[(x+3)^2 -1]
Your answer should not have absolute value | | symbols around x+3, and needs brackets around (x+3)^2 -1, to show that you take the square root of everything in brackets.
I just want to make sure im right. Find the derivative if y= arcsec(x+3).
I got
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|x+3|sqrt(x+3)^(2)-1
Is this the final answer or do you need to solve (x+3)^2 and get (x^(2) + 9x + 9)
1 answer
1 answer