Question

I just realised... AB*BC*AC = AABBCC = (ABC)^2
So to find ABC you just do sqr(1216*2812*2368)

Answer 1

It looks like you're working with some algebraic manipulations related to products of numbers and their arrangement. The expression you've provided, \(AB \times BC \times AC = AABBCC\), suggests a relationship between the products of three variables and a concatenated number representation.

To verify your expression \(AB \times BC \times AC = (ABC)^2\):

1. **Rearranging the Expression**:
- \(AB\) represents the product of \(A\) and \(B\).
- \(BC\) represents the product of \(B\) and \(C\).
- \(AC\) represents the product of \(A\) and \(C\).

Therefore, the multiplication of these three gives:
\[
AB \times BC \times AC = (A \times B) \times (B \times C) \times (A \times C) = A^2 \times B^2 \times C^2 = (ABC)^2
\]

2. **Calculating \((ABC)\)**:
If you're suggesting that \(ABC\) can be calculated through the expression \(\sqrt{1216 \times 2812 \times 2368}\), that is an interesting approach!

Following this:

\[
ABC = \sqrt{1216 \times 2812 \times 2368}
\]

You would need to compute that multiplication and then take the square root.

Using a calculator or computation tool, you can confirm this calculation. If you want the exact value or further assistance in calculating, feel free to ask!