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Penguinshade
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I just realised... AB*BC*AC = AABBCC = (ABC)^2
So to find ABC you just do sqr(1216*2812*2368)
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for some reason no one got it, im sure oobleck knew how to do it but he didnt include the answer >.< 1. 1216 = 2^6 * 19 (A*B) 2. 2812 = 2^2 * 19 * 37 (B*C) 3. 2368 = 2^6 * 37 (A*C) in 1. and 2. both had "B" and both also had 19 and 2^2. so B=19*2^2/2,
