Nope. 2^n goes
2,4,8,16,32,64,...
So, 2^n-1 goes
1,3,7,15,31,63,...
Your sequence is 2*n, not 2^n
I have to find the five terms in geometric sequence in this
a(lower n)= (2)^n-1
I would do it 2(1)+2(2)+(2(3)+2(4)+2(5)
so 2,4,6,8,10
Did I do this correctly??
2 answers
Actually, none of the sequences I gave is a geometric sequence. For that you need
an = 2^(n-1)
1,2,4,8,16,...
where each pair of terms has a common ratio, in this case, 2.
an = 2^(n-1)
1,2,4,8,16,...
where each pair of terms has a common ratio, in this case, 2.
2 answers