i have to find the derivative (first) of

Question

y= tan^2 (3x-π)

^that is (3x- pi)

Answer 1

Use the power rule

y= a^u
y'= u a^(u-1) da/dx

y'= 2tan( ) d tan(3x-PI)/dx
= 2 tan ( )* sec^2( ) * 3