i have this question and i kinda know how to do it but i'm not entirelly sure.
here's the problem
x-5/4 = x+5/x+2
if you can help great and thank you
2 answers
Please use parentheses to rewrite your problem. For example, x-(5/4) = x+(5/x) + 2 or whatever; otherwise, we can't tall what is in the numerator and whatr is in the denominator.
x-5 x+5
___ = ___
4 x+2
First you want to cross multiply
(x-5)(x+2) = 4(x+5)
Then use FOIL on the left hand side, and distribute the 4 on the right hand side
to get X(squared)-3x -10 on the left
= 4x+20 on the right
subtract the 4x+20 on the right and left side
you get x(squared) -7x -30 =0
now find the roots of this equation
(x-10)(x+3)=0
x=10 and x=-3
Those are the solutions for x
___ = ___
4 x+2
First you want to cross multiply
(x-5)(x+2) = 4(x+5)
Then use FOIL on the left hand side, and distribute the 4 on the right hand side
to get X(squared)-3x -10 on the left
= 4x+20 on the right
subtract the 4x+20 on the right and left side
you get x(squared) -7x -30 =0
now find the roots of this equation
(x-10)(x+3)=0
x=10 and x=-3
Those are the solutions for x