I have some questions regarding motion problems.

Question

If I have a ball at initial velocity of 50m/s at 35 degree angle, to find horizontal and vertical components, I do the following:
Vertical is 50(sin35)=28.68-rounded to 29
Horizontal = 50 (cos 35)=40.96-rounded to 42
Maximum height ball hit 29 m/s^2 /2(9.81m/s^2)= 42.90
Range of ball:29/4.92 = 5.9 s
take 41 (horizontal velocity) times 2 =84 meters

Could you just check this for me-thank you-if its wrong, just direct me where I did it incorrectly

Answer 1

Just please check my calculations-

Answer 2

Yes, I agree, but I would not have rounded to two significant figures, it pains me to to do that.

Answer 3

Hi, I think I did the range calculation incorrectly-Shouldn't I have done:
Horizontal 40.96 times 5.9 s, not 2-I'm not sure where I got the two
My new answer should be 40.96 x 5.9 = 241.66m

I'll remember about rounding

Answer 4

yes, I missed that on the time.

Answer 5

Thanks for your help I really appreciated it!!