oops it didn't write the question like i wanted it to, here I'll fix it
4x/x^2-9 - 5x/x^2+4x-+3
I have one more question I need to ask about algebra, this one is a perform the indicated operation question.
4x 5x
----- - ----
x^2-9 x^2+4x-+3
I am really confused on the -+3 part, I don't know if my teacher made a typo or what, because without the - in that part it would be easily factorable.
2 answers
I also think the -+ is a typo error by your teacher. Assume it is +
Then you have
4x/[(x+3)(x-3)] - 5x/[(x+3)(x+1)]
= [1/(x+3)][4x(x+1)-5x(x-3)]/[(x+1)(x-3)]
= [1/(x+3)][-x^2+19x]/[(x+1)(x-3)]
= -x(x-19)/[(x+1)(x-3)(x+3)]
I don't guarantee I did that right. I created a common denominator, but it is still pretty messy.
Then you have
4x/[(x+3)(x-3)] - 5x/[(x+3)(x+1)]
= [1/(x+3)][4x(x+1)-5x(x-3)]/[(x+1)(x-3)]
= [1/(x+3)][-x^2+19x]/[(x+1)(x-3)]
= -x(x-19)/[(x+1)(x-3)(x+3)]
I don't guarantee I did that right. I created a common denominator, but it is still pretty messy.