I have not learned this yet in class and I am stuck on this homework problem.
Graph the linear equation by using a table of solutions.
3x-4y=12
4 answers
Why are you trying to do this problem before you've learned how to do it in class?
An assignment with 3 of these problems was assigned to my class and we haven't learned it yet. I don't know when our professor plans on covering it but I'd like to finish my homework.
A linear equation of your type will produce a straight line when graphed.
So all you need are 2 distinct points.
Using the x and y intercepts are a quick and easy way to do this, after all the intercepts are just plain ol' points.
Here is an easy way to do this:
let x = 0
put your pinkie finger or a pencil over the x term, leaving you with -4y = 12, so y = -3
you got the y-intercept, (0,-3)
let y = 0 , again put your pinkie over the y term, leaving you looking at 3x = 12 , so x = 4
x-intercept is (4,0)
plot (4,0) and (0,-3), draw the line passing through those two points.
This method works really well if the constant is divisible by both the x and y coefficients, like it was for your equation.
So all you need are 2 distinct points.
Using the x and y intercepts are a quick and easy way to do this, after all the intercepts are just plain ol' points.
Here is an easy way to do this:
let x = 0
put your pinkie finger or a pencil over the x term, leaving you with -4y = 12, so y = -3
you got the y-intercept, (0,-3)
let y = 0 , again put your pinkie over the y term, leaving you looking at 3x = 12 , so x = 4
x-intercept is (4,0)
plot (4,0) and (0,-3), draw the line passing through those two points.
This method works really well if the constant is divisible by both the x and y coefficients, like it was for your equation.
thank you so much!!
1 answer