I have no idea how to do this question. Would be appreciated if someone help =)

The velocity of a car is given by v(t)=60(1-[0.7]^t), where v is measured in m/s and t is measured in s. Determine the following:

a)What is the acceleration function?

b) What is the accerlation at t=2s?

c)What is the initial velocity?

d)What is the time at which the accleration is 3m/s^2?

2 answers

I assume you have calculus.

a= dv/dt= d(60-60*.7t)/dt=-60*.7^t * ln0.7
Yes, I do have calculus.

So the acceleration function is -60(0.7t)(In0.7)

b) What is the accerlation at t=2s?

-60(0.7(2))(In0.7)= 29.996.

The acceleration would be 29.99 m/s^2?
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How do I do part c and d?