Lets look at the outcomes:
product: 6
ways 2x3, 3x2, 1x6,6x1
Product:8
ways:2x4,4x2
product: 4
ways: 4x1,1x4, 2x2
product:7
no ways
so it appears six is most likely.
I have no clue as to how to tackle this problem.
Two standard six-sided dice are rolled. The product of their outcomes is computed. Which of the following numbers is most likely to occur?
4
6
7
8
2 answers
But if one dice has a 6 face up and the other dice has a 1 face up, isn't that a product of 7?