ummm, why would you use acetic acid to prepare a NaOH solution?
Anyway, 250mL of .5M NaOH contains .125 moles NaOH = .125(23+16+1) = 5 grams
I have a project practical investigation to do and I have no idea how to go about with it. The problem is: Calculate the mass of sodium hydroxide used to prepare a 0,5M NaOH solution in a 250ml volumetric flask. Determine the concentration of the acetic acid solution used (vinegar).
3 answers
.25L times .5M=.125moles
.125 times 40= 5 grams
.125 times 40= 5 grams
They did the right work but the answer is 40 grams. That is what it says in the book.