It is best to post questions separately. Better chance of getting both of them worked.
m = moles/kg solvent
solve for m since you have moles and g solvent.
Then delta T = i*Kf*m
i for NaCl = 2.
I forgot to post this one with the other
What is the freezing point of a solution containing 4.0 Mol of sodium chloride in 1200 grams of water? (kf for water is 1.86 C/M)
I don't really want the whole answer, just where I would plug in the numbers. I keep forgetting what formula to use.
3 answers
m = 4.0/1200 = 300
T = 2*1.86 c/m*300 = 1116
T = 2*1.86 c/m*300 = 1116
Nope. m = moles/Kg solvent. That is 1.2 and not 1200
and T is not the same as delta T. delta T is how much the freezing point has changed. The normal freezing point of water is 0 degrees C so detla T will decrease it by that much. I get something like -12.4 C.
and T is not the same as delta T. delta T is how much the freezing point has changed. The normal freezing point of water is 0 degrees C so detla T will decrease it by that much. I get something like -12.4 C.
1 answer