make a table of x and y in columns
to start
x y
0 3
4 0
seeing as how this is a straight line, just put those two points on your graph and draw a straight line through them.
or if you do not believe that, find some more points:
1 9/4
2 3/2
3 3/4
4 0
5 -3/4 etc
i don't understand how to graph an equation. can anyone help me please? i'll greatly appreciate it.
Example: 3x+4y=12
6 answers
thanks a whole bunch. i have just one more question how can you tell whether an equation represents a direct variation?
A direct variation means the graph goes through the origin (0,0) and the output is proportional to a power of the input like
y = x
or
y = x^2
or
y = x^3
or
y = 5 x
or
y = 15 x^2
But NOT
y = x^2 + 3
y = x
or
y = x^2
or
y = x^3
or
y = 5 x
or
y = 15 x^2
But NOT
y = x^2 + 3
hey can you also help me out with this problem?
x+2y-4=0
just explain to me step by step so i won't have to bother you anymore. Thanx :P !!!!!!!
x+2y-4=0
just explain to me step by step so i won't have to bother you anymore. Thanx :P !!!!!!!
That is just the equation of a straight line like the earlier one.
Try x = 0
2 y = 4
y = 2
so (0,2) is on your line
Now try y = 0
x = 4
so (4,0) is on your line.
graph those two points, put a straight line through them.
Try x = 0
2 y = 4
y = 2
so (0,2) is on your line
Now try y = 0
x = 4
so (4,0) is on your line.
graph those two points, put a straight line through them.
ohhh i get it. so when you solve for x, you put y as 0. Then when you solve foy y, you put x as 0. am i right?
1 answer