Yes, but count brackets. I try to use different ones
log^-1[ x(log 7 - log 8) ]
I don't if I'm right for these two questions i just need a check if I'm right,if I'm wrong please show me how to get that answer.
Rewrite the following exponential functions as logarithmic functions
a)f(x)=9^x
ans:f(x) Log^-1(xlog(9))
b)f(x)=(7/8)^x
ans:log^-1(x(log 7 - log 8)
i don't know if I'm right for the answer,so i just need to know and if I'm wrong prove please show me how to be right.
6 answers
Okay i was wondering because some people told me the answer is log(f(x))=2xlog(3)
For a)
well
9^x = 3^(2x)
so log^-1 (2 x log 3)
is a perfectly good answer. So is Log^-1(xlog(9))
They are the same :)
9^x = 3^(2x)
so log^-1 (2 x log 3)
is a perfectly good answer. So is Log^-1(xlog(9))
They are the same :)
So i guess my answer is acceptable right :)
I think your answer is fine. So is the 3^2 = 9 one.
1 answer