I do not understand point-slope and standard form. Please help me.

5 answers

Can you be more specific with your question?
Is the "standard form" y = mx + b ?
Example: point slope is y+5=-4/1(x+3)

y + 5 = 4(x+3)

y + 5 = 4x + 12

subtract 5 on both sides.

y = 4x + 7

subtract 4x on both sides.

-4x + y = 7

divide both sides by -1.

[[ 4x - y = -7 ]]

You can search on websites and have some examples like this one
Thanks!
How would you know whether to add or subtract?
Solve for y = mx + b or y - y1 = m (m - x1). Your line will be in slope intercept form.

Now add/subtract/multiply/divide in order to get to Ax + By = C, where A,B&C are non-fractions and A>0.

For example: Write the equation of a line in standard form that has a slope of 4 and passes through (-3,5).

y - y1 = m (x - x1)

y - 5 = 4 (x - (-3))

y - 5 = 4x + 12

Add 5 to both sides.

y = 4x + 17

Subtract 4x from both sides to get the variables on the same side.

-4x + y = 17

The pattern for Standard Form shows that the coefficient with x can't be negative when it expresses A>0. So, multiply everything by -1, keeping in mind you can do anything to an equation and it will remain true as long as you do it to both sides.

-1(-4x + y = 17)

4x - y = -17

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Thank you.