Asked by Jay
Please Help! I don't understand the question asking.
The greatest common factor of 12m^5n^3 + 18m^3n^3 - 24m^2n^3 is Am^bn^c, where A,B and C are whole numbers?
The greatest common factor of 12m^5n^3 + 18m^3n^3 - 24m^2n^3 is Am^bn^c, where A,B and C are whole numbers?
Answers
Answered by
Henry
12 = (1*12), (2*6), (3*4).
18 = (1*18), (2*9), (3*6).
24 = (1*24), (2*12), (3*8), (4*6).
CF = 1,2,3,6.
GCF = 6.
So we factor out 6 and the variables with the lowest exponents:
6m^2n^3(2m^3 + 3m - 4)
I, normally, find the GCF by knowing that the GCF =< 12 (the smallest coefficient). If 12 is too large, try
1/2 of 12, and 1/3 of 12 and etc.
18 = (1*18), (2*9), (3*6).
24 = (1*24), (2*12), (3*8), (4*6).
CF = 1,2,3,6.
GCF = 6.
So we factor out 6 and the variables with the lowest exponents:
6m^2n^3(2m^3 + 3m - 4)
I, normally, find the GCF by knowing that the GCF =< 12 (the smallest coefficient). If 12 is too large, try
1/2 of 12, and 1/3 of 12 and etc.
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