2nd term = 24
5th term = 3
24-3 = 21
5-2 = 3
21/3 = 7
common difference = -7 since the terms are decreasing
so to find the first term, subtract -7 from 24
so the first term is equal to 31
I can't solve this one:
The second term of an arithmetic sequence is 24 and the fifth term is 3.Find the first term and the common difference.
How could I get the answers if there's only two given numbers?
4 answers
traditional method:
a+d = 24
a+4d = 3
subtract them:
3d = -21
d = -7
sub into a+d = 24
a - 7 = 24
a = 31
first term is 31, commond difference is -7
a+d = 24
a+4d = 3
subtract them:
3d = -21
d = -7
sub into a+d = 24
a - 7 = 24
a = 31
first term is 31, commond difference is -7
how many terms are there in an arithmetic sequence those first term is -4 common difference 2 and last term is 24?
The second term if can arithmetic sequence is 24 and the fifth term is 3 find the first term and common difference