I am trying to find:

Question

dy/dx for y = sec(tan x)

I have the answer, but I have no idea how to get there. I know that the derivative of sec x = sec x tan x and that the derivative of tan x is sec^2 x. But sec doesn't have an x, so ...?

Answer 1

d/dx secu = secu tanu du/dx, so
y' = sec(tanx) tan(tanx) sec^2(x)

Answer 2

thanks!!!!!!