Ask a New Question
Search
I am having trouble figuring out how to solve this logarithms. Could someone please help!
log2(log4x)=1 and
solve for x and y:
(1/2)^x+y= 16 logx-y8=-3
Ask a New Question
or
answer this question
.
Similar Questions
I am having trouble figuring out how to solve these logarithms. Could someone please help!
log2(log4x)=1 and solve for x and y:
1 answer
I am having trouble figuring out how to solve these logarithms. Could someone please help!
log2(log4x)=1 and solve for x and y:
1 answer
solve the equation
log2(x+4)-log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2
1 answer
i need help with these two homework problems
Use the Laws of Logarithms to combine the expression into a single logarithm log2 5
1 answer
more similar questions