I am having trouble figuring out how to solve these logarithms. Could someone please help!
log2(log4x)=1 and
solve for x and y:
(1/2)^x+y= 16 logx-y8=-3
1 answer
Answered in a later post.
log2(log4x)=1 and
solve for x and y:
(1/2)^x+y= 16 logx-y8=-3
1 answer