1. Substitute 8-3y for y in the first equation and solve the reulting equation in y only.
2. The slope of the line connecting those points is the change in y divided by the change in x between the two points.
3. If "some number" is called x, 46% of that number is 0.46 x
Please make an effort to solve these yourself and show your work if you need further help
I am having a really hard time with these!
1. Solve system of equations
x+3y=7 (1)
x=8-3y (2)
2. find slope
(9,8) (10,-7)
3. translate into an algebraic expression
The product of 46% and some number
2 answers
1. Solve system of equations
x+3y=7 (1)
x=8-3y (2)
You can "substitute", use the x from the first equation in the second like this:
x = 7 - 3 y from first, use in second
7 -3y = 8 -3y
As you can see, that is impossible. You have been given a set of equations that represent two parallel lines that never cross. There is no solution.
2. find slope
(9,8) (10,-7)
chnge in y / change in x
= (-7 - 8) / (10 - 9)
= -15/1
= -15
3. translate into an algebraic expression
The product of 46% and some number
46%/100 = 0.46
so
y = 0.46 x
x+3y=7 (1)
x=8-3y (2)
You can "substitute", use the x from the first equation in the second like this:
x = 7 - 3 y from first, use in second
7 -3y = 8 -3y
As you can see, that is impossible. You have been given a set of equations that represent two parallel lines that never cross. There is no solution.
2. find slope
(9,8) (10,-7)
chnge in y / change in x
= (-7 - 8) / (10 - 9)
= -15/1
= -15
3. translate into an algebraic expression
The product of 46% and some number
46%/100 = 0.46
so
y = 0.46 x
9 answers