I am a three digit number. My hundreds digit is five more than my once digit. My tens digit is 8 less than my hundreds digit. What number am I?

Answer 1

Your number:

A B C

where

A = hundreds digit

B = tens digit

C = once digit

with conditions:

A ≤ 9

B ≤ 9

C ≤ 9

Hundreds digit is five more than my once digit mean:

A = C + 5

so

C = A - 5

Tens digit is 8 less than my hundreds digit mean:

B = A - 8

B = C + 5 - 8

B = C - 3

so

C = B + 3

C = C

A - 5 = B + 3

Add 5 to both sides

A = B + 3 + 5

A = B + 8

Subtract B to both sides

A - B = 8

Since A ≤ 9 and B ≤ 9

This is possible only if :

A = 9 , B = 1

so

A = 9

B = 1

C = A - 5

C = 9 - 5

C = 4

OR

C = B + 3

C = 1 + 3

C = 4

Your number A B C is 9 1 4

Answer 2

could also be
803