I aked the instructor about that problem that looked like this:
(w-(1)/(4))^2
and he said that what i thought was right. which was :
the answer:w^2-(1)/(2)w+(1)/(6)
Yes, that's right. I just thought your way of getting the answer was more complicated than it could have been.
With the placement of the parentheses in your answer I can't tell what you have, but I can tell you for sure that what Belinda wrote yesterday; i.e.,
[(w-1)/4]2 =
(w2 -2w +1)/16 is correct. That answer may be modified somewhat by certain arithmetic procedures but squaring w-1 MUST give, at least as a first step, w2 -2w +1.
see dr.bob222
then why did the instructor say that this was wrong about
w2 -2w +1
he said it had to be:
w squared and negative one half w plus one over sixteen.
We aren't working the same problem. And the reason for that is that you didn't use parentheses correctly. You are working this problem.
(w-(1)/(4))^2
Written as you should have written it is
[w-(1/4)]2
That give you
w2 - 0.5w + 1/16 which agrees with your previous answer and the teacher's answer.
I worked this one
[(w-1)/4]2
which gives the answer I posted yesterday.
(w2 -2w + 1)/16
I hope this clears things up.
3 answers